Tìm x,y,z biết xy=16z yz=-25x xz=-9y Question Tìm x,y,z biết xy=16z yz=-25x xz=-9y in progress 0 Môn Toán Acacia 6 years 2020-11-21T17:15:49+00:00 2020-11-21T17:15:49+00:00 1 Answers 89 views 0
Answers ( )
Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
\left\{ \begin{array}{l}
xy = 16z\\
yz = – 25x\\
xz = – 9y
\end{array} \right.\\
\Rightarrow \left( {xy} \right).\left( {yz} \right).\left( {zx} \right) = 16z.\left( { – 25x} \right).\left( { – 9y} \right)\\
\Leftrightarrow {\left( {xyz} \right)^2} = 3600xyz\\
\Leftrightarrow xyz = 3600\\
\Rightarrow \left\{ \begin{array}{l}
xy = \dfrac{{3600}}{z}\\
yz = \dfrac{{3600}}{x}\\
zx = \dfrac{{3600}}{y}
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
16z = \dfrac{{3600}}{z}\\
– 25x = \dfrac{{3600}}{x}\\
– 9y = \dfrac{{3600}}{y}
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
{z^2} = 225\\
{x^2} = – 144\\
{y^2} = – 400
\end{array} \right.
\end{array}\)
Hệ trên vô nghiệm do \({x^2},{y^2},{z^2} \ge 0\)