Lô nhìn dõ giúp mình

Question

Lô nhìn dõ giúp mình
lo-nhin-do-giup-minh

in progress 0
RI SƠ 4 years 2020-11-21T08:12:43+00:00 1 Answers 60 views 0

Answers ( )

  1. Bo
    0
    2020-11-21T08:14:20+00:00
    Reply

    Đáp án:

     Bài 1)
    $1)x=\dfrac{-3}{4}\\
    2)
     {\left[\begin{aligned}x=\dfrac{1}{6}\\x=\dfrac{2}{3}\end{aligned}\right.}$
    Bài 2)
    $1) \dfrac{1}{3}\\
    2) 0,000001\\
    3)1\\
    4)1\\
    5)4$

    Giải thích các bước giải:

     Bài 1)
    $1) \left | x+\dfrac{3}{4} \right |=0\\
    \Leftrightarrow x+\dfrac{3}{4}=0\\
    \Leftrightarrow x=\dfrac{-3}{4}\\
    2)
    \left | \dfrac{5}{12}-x \right |+\dfrac{3}{8}=\dfrac{5}{4}\\
    \Leftrightarrow \left | \dfrac{5}{12}-x \right |=\dfrac{5}{4}-\dfrac{3}{8}\\
    \Leftrightarrow  \left | \dfrac{5}{12}-x \right |=\dfrac{10}{8}-\dfrac{3}{8}\\
    \Leftrightarrow  \left | \dfrac{5}{12}-x \right |=\dfrac{2}{8}=\dfrac{1}{4}\\
    \Leftrightarrow {\left[\begin{aligned}\dfrac{5}{12}-x=\dfrac{1}{4}\\\dfrac{5}{12}-x=\dfrac{-1}{4}\end{aligned}\right.}\\
    \Leftrightarrow {\left[\begin{aligned}x=\dfrac{5}{12}-\dfrac{1}{4}\\x=\dfrac{5}{12}+\dfrac{1}{4}\end{aligned}\right.}\\
    \Leftrightarrow {\left[\begin{aligned}x=\dfrac{5}{12}-\dfrac{3}{12}\\x=\dfrac{5}{12}+\dfrac{3}{12}\end{aligned}\right.}\\
    \Leftrightarrow {\left[\begin{aligned}x=\dfrac{2}{12}=\dfrac{1}{6}\\x=\dfrac{8}{12}=\dfrac{2}{3}\end{aligned}\right.}$
    Bài 2)
    $1) \left ( \dfrac{-1}{3} \right )^2:\dfrac{1}{3}=\left ( \dfrac{1}{3} \right )^2:\dfrac{1}{3}=\dfrac{1}{3}\\
    2) [(0,1)^3]^2=(0,001)^2=0,000001\\
    3)
    \left [ \left ( \dfrac{-1}{27} \right )^0 \right ]^3\\
    =1^3=1\\
    4)
    \left ( \dfrac{1}{7} \right )^7.7^7\\
    =\dfrac{1^7}{7^7}.7^7\\
    =1\\
    5)
    (0,25)^4.1024\\
    =\dfrac{1}{256}.1024\\
    =4$

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )