Giúp mình với ạ. …. Question Giúp mình với ạ. …. in progress 0 Môn Toán Jezebel 4 years 2020-11-13T19:22:02+00:00 2020-11-13T19:22:02+00:00 2 Answers 54 views 0
Answers ( )
`ĐK: x ne π/2 + kπ`
`PT`
`=> cos² x – sin x.cos x = 1`
`<=> -(1 – cos² x) – sin x.cos x = 0`
`<=> – (sin² x + sin x.cos x) = 0`
`<=> sin x(sin x + cos x) = 0`
`<=>` \(\left[ \begin{array}{l}sin x = 0\\sin x + cos x = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = kπ\\cos x = sin (-x)\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = kπ\\cos x = cos (\dfrac{\pi}{2} + x)\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = kπ\\x = -\dfrac{π}{2} – x + k2π\\x = \dfrac{π}{2} + x + k2π\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = kπ\\x = -\dfrac{π}{4} + kπ\end{array} \right.\) `( k ∈ ZZ)`
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