f(x) = x2 + x + 1 6(x-4) SERE g(x) = x2+x+1 8(x-4) Which statement comparing the oblique asymptotes of t

Question

f(x) =
x2 + x + 1
6(x-4)
SERE
g(x) = x2+x+1
8(x-4)
Which statement comparing the oblique asymptotes of the functions f(x) and g(x) is true?
The oblique asymptote for g(x) is steeper than for f(x).
Both functions have the same oblique asymptote.
The oblique asymptote for f(x) is steeper than for g(x).
Both functions have parallel oblique asymptotes.

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Vân Khánh 3 years 2021-09-04T08:57:35+00:00 1 Answers 7 views 0

Answers ( )

  1. thugiang
    0
    2021-09-04T08:59:00+00:00
    Reply

    Answer:

    The oblique asymptote fo f(x) is steeper than for g(x).

    Step-by-step explanation:

    Just took the test and got it right

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