The area of the rectangle is greater than 60 square feet. Identify and solve the inequality that can be used to find the possible values of

Question

The area of the rectangle is greater than 60 square feet. Identify and solve the inequality that can be used to find the possible values of x. Question 1 2(12)+2(2x−3)>60 12(2x−3)≥60 12+2x−3>60 12(2x−3)>60

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Dulcie 4 years 2021-08-27T09:33:14+00:00 1 Answers 225 views 0

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  1. King
    1
    2021-08-27T09:35:10+00:00
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    Answer:

    D. 12(2x − 3) > 60

     ii. x > 4

    Step-by-step explanation:

    Area of rectangle = length x width

    The length of the rectangle is 12 feet, and the width is (2x – 3) feet.

    Area = 12 x (2x – 3)

            = 12(2x – 3)

    From the given question,

    area of rectangle > 60 square feet

    So that;

    12(2x – 3) > 60

    24x – 36 > 60

    24x > 60 + 36

    24x > 96

    Divide both sides by 24, to have;

    \frac{24x}{24} = \frac{96}{24}

    x > 4

    Therefore,

    width = (2x -3)

    since x > 4, then;

    width  > (2×4 – 3)

              > 8 -3

    width > 5 feet

    Thus,

    length x width > 60

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