(x+1)(x-1)(x²+x+1)(x²-x+1) Question (x+1)(x-1)(x²+x+1)(x²-x+1) in progress 0 Môn Toán Eirian 4 years 2020-11-04T16:01:46+00:00 2020-11-04T16:01:46+00:00 2 Answers 54 views 0
Answers ( )
Đáp án: `x^6-1`
Giải thích các bước giải:
`(x+1)(x-1)(x^2+x+1)(x^2-x+1)`
`=[(x+1)(x^2-x+1)].[(x-1)(x^2+x+1)]`
`=(x^3+1)(x^3-1)`
`=(x^3)^2-1`
`=x^6-1`
`(x+1)(x-1)(x^2+x+1)(x^2-x+1)`
`=[(x+1)(x^2-x+1)][(x-1)(x^2+x+1)]`
`=(x^3+1)(x^3-1)=x^6-1`