The function F is defined by f(x)=x^2-5x+6. What is the value of f(4)?

Question

The function F is defined by f(x)=x^2-5x+6. What is the value of f(4)?

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King 5 years 2021-08-11T17:14:07+00:00 2 Answers 22 views 0

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  1. dangkhoa
    0
    2021-08-11T17:15:21+00:00
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    f(x)=x^2-5x+6

    ↝ f(4) equals to substituting x = 4 in the equation.

    Thus,

    f(4)=4^2-5(4)+6\\f(4)=16-20+6\\f(4)=22-20\\f(4)=2

    Therefore, f(4) = 2

  2. huyenthanh
    0
    2021-08-11T17:15:32+00:00
    Reply

    Answer:

    2

    Step-by-step explanation:

    f(4) = 4^2-5(4) + 6

         = 2

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