construct a ​99% confidence interval of the population proportion using the given information. x=240 n=300

Question

construct a ​99% confidence interval of the population proportion using the given information. x=240 n=300

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MichaelMet 5 years 2021-08-06T12:07:14+00:00 1 Answers 38 views 0

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  1. minhkhue
    0
    2021-08-06T12:08:44+00:00
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    Confidence interval for population proportion is

    sample proportion +/- confidence coefficient*standard error of p

    Sample proportion = p = x/n = 180/300 = 0.6

    Confidence coefficient is the critical value of z for 95% confidence level = 1.96

    Standard error of p = sqrt [p*(1-p)/n]

    = sqrt [0.6*0.4/300]

    = 0.0283

    The CI is

    0.6 +/- 1.96*0.0283

    0.6 +/- 0.055

    lower boundary is 0.6-0.055 = 0.545

    upper boundary is 0.6+0.055 = 0.655

    The CI is (0.545, 0.655)

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