A natural number is multiplied by itself. Is it possible to have 66 at the rightmost end?

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A natural number is multiplied by itself. Is it possible to have 66 at the rightmost end?

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Thành Công 4 years 2021-08-05T20:17:23+00:00 1 Answers 37 views 0

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  1. thienhuong
    0
    2021-08-05T20:18:31+00:00
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    simple logic for this is :-

    for example

    11*11=121 (11 is 2 one’s so from 1 till 2 and back )

    111*111 =12321 (111 is 3 one’s so count from 1 till 3 and back ) that is 1 2 3 and back 2 1

    similarly for 12345678987654321 =111,111,111(9 one’s) *111,111,111

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