3. Given the following equation: 2 K+ Cl2 =>2 KCI How many grams of KCl are produced from 2.50 g of K and excess Cl2?

Question

3. Given the following equation:
2 K+ Cl2 —>2 KCI
How many grams of KCl are produced from 2.50 g of K and excess Cl2?

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niczorrrr 4 years 2021-08-27T15:34:13+00:00 1 Answers 14 views 0

Answers ( )

  1. Giakhanh
    0
    2021-08-27T15:36:06+00:00
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    Answer:

    4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

    Explanation:

    The balanced equation is

    2 K+ Cl2 —>2 KCI

    Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

    Mass of one atom/mole of potassium is 39.098 grams

    Number of moles is 2.5 grams = \frac{2.5}{39.098} = 0.064

    So, 2 moles of K produces 2 moles of KCL

    0.064 moles of K will produces 0.064 moles of KCl

    Mass of one molecule of KCl is 74.5513 g/mol

    Mass of 0.064 moles of KCl is 4.767 grams

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