10N force isn’t applied to a hockey puck over a period of 0.1s. What is the change in momentum of the hockey puck

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Physics Mít Mít 4 years 2021-08-22T05:22:18+00:00 2021-08-22T05:22:18+00:00 1 Answers 13 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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Jezebel · Answer 1 · 2021-08-22T05:23:22+00:00

Jezebel

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2021-08-22T05:23:22+00:00 August 22, 2021 at 5:23 am

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Answer:

$\Delta p = 1.0 \ \rm N.s$

Explanation:

Given data:

Force, $F = 10 \ \rm N$

Time period, $t = 0.1 \ s$

The change in momentum experienced by the puck can be given as,

$\Delta p = F \times t$

$\Delta p = 10 \ \rm N \times 0.1 \ s$

$\Delta p = 1.0 \ \rm N.s$