1. If you use an applied force of 45N to slide a 12Kg wooden crate across a floor at a constant velocity, what is the coefficient of kinetic

Question

1. If you use an applied force of 45N to slide a 12Kg wooden crate across a floor at a constant velocity, what is the coefficient of kinetic friction between the crate and the floor?

in progress 0
Kim Chi 5 years 2021-07-30T14:40:35+00:00 1 Answers 25 views 0

Answers ( )

  1. Acacia
    0
    2021-07-30T14:42:13+00:00
    Reply

    Answer:

    Coefficient of kinetic friction = 0.38 (Approx.)

    Explanation:

    Given:

    Applied force = 45 N

    Mass of wooden crate = 12 kg

    Find:

    Coefficient of kinetic friction

    Computation:

    Coefficient of kinetic friction = Applied force / (Mass)(Acceleration due to gravity)

    Coefficient of kinetic friction = 45 / (12)(9.8)

    Coefficient of kinetic friction = 45 / 117.6

    Coefficient of kinetic friction = 0.3826

    Coefficient of kinetic friction = 0.38 (Approx.)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )