1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?​

Question

1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?​

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Sapo 4 years 2021-09-01T01:14:41+00:00 1 Answers 71 views 0

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  1. bonexptip
    0
    2021-09-01T01:15:48+00:00
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    Answer:

    0.01 moles of SrCO₃

    Explanation:

    In this excersise we need to propose the reaction:

    K₂CO₃ + Sr(NO₃)₂  →  2KNO₃ + SrCO₃

    As we only have data about the potassium carbonate  we assume the strontium nitrite as the excess reactant.

    1 mol of K₂CO₃ react to 1 mol of Sr(NO₃)₂ in order to produce 2 moles of potassium nitrite and 1 mol of strontium carbonate.

    Ratio is 1:1. In conclussion,

    0.01 mol of K₂CO₃ must produce 0.01 moles of SrCO₃

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