1. Find the value of x. x - \sqrt{6} \div \sqrt{3} + \sqrt{2} = 3 \sqrt{3} - 4 \sqrt{2} \div 1 ​

Question

1. Find the value of x.

x - \sqrt{6} \div \sqrt{3} + \sqrt{2} = 3 \sqrt{3} - 4 \sqrt{2} \div 1
​

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Đan Thu 4 years 2021-09-03T19:58:56+00:00 1 Answers 11 views 0

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  1. MichaelMet
    0
    2021-09-03T20:00:17+00:00
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    Answer:

    x = - 0.461

    Step-by-step explanation:

    x - \sqrt{2 } + \sqrt{2} = 3 \sqrt{3} - 4 \sqrt{2} \\ x = 3 \sqrt{3} - 4 \sqrt{2} \\ x = - 0.461

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