1.35 m solution NaOCl in water is prepared. What is the mole fraction of the NaOCl?

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1.35 m solution NaOCl in water is prepared. What is the mole fraction of the NaOCl?

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Orla Orla 3 years 2021-08-30T22:24:36+00:00 1 Answers 66 views 0

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  1. ngocdiep
    -1
    2021-08-30T22:26:35+00:00
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    Answer:

    NaOCl + H2O → HOCl + NaOH

    so the mole fraction is = moles of NaOCl/(moles of NaOCl+moles of H2O)

    so for 1.35 NaOCl it will require 1.35 moleof H2O

    mole fraction = 1.35/(1.35+1.35)

    mole fraction = 1/2 =0.5

    is it correct i d ek but i tried 🙂

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