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## Suzanne observes two light pulses to be emitted from the same location, but separated in time by 3.00 μs. Mark sees the emission of the same

Question

Suzanne observes two light pulses to be emitted from the same location, but separated in time by 3.00 μs. Mark sees the emission of the same two pulses separated in time by 9.00 μs. (a) How fast is Mark moving relative to Suzanne? (b) According to Mark, what is the separation in space of the two pulses?

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Physics
5 months
2021-08-28T10:59:01+00:00
2021-08-28T10:59:01+00:00 1 Answers
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## Answers ( )

Given that,Separated in time t = 3.00 μs

Separated in time t’ = 9.00 μs

(a). We need to calculate the speedUsing formula of time dilationPut the value into the formula

(b). The separation that Mark sees is just the time he sees between the pulse times the speed of light,Since the first pulse is moving at that speed

We need to calculate the separation in space of the two pulsesUsing formula of separationPut the value into the formula

Hence, (a). The speed of mark relative to Suzanne is 0.942c.(b). The separation in space of the two pulses is 2700 m.