How much heat is absorbed when 63.7 g H2O(l) at 100 degrees Celsius and 101.3kPa is converted to steam at 100

Question

How much heat is absorbed when 63.7 g H2O(l) at 100 degrees Celsius and 101.3kPa is converted to steam at 100

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Minh Khuê 5 years 2021-07-30T01:24:32+00:00 1 Answers 175 views 0

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  1. thachthao
    0
    2021-07-30T01:25:57+00:00
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    Answer:

    Q = 143,921 J = 143.9 kJ.

    Explanation:

    Hello there!

    In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:

    Q=m*\Delta _{vap}H

    Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:

    Q=63.7g*2259.36J/g\\\\Q=143,921J=143.9kJ

    Regards!

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