charlyn walks completely around the boundary of a square whose sides are each 55 km long. from any point on her path she can see e

by

charlyn walks completely around the boundary of a square whose sides are each 55 km long. from any point on her path she can see exactly 11 km horizontally in all directions. what is the area of the region consisting of all points charlyn can see during her walk, expressed in square kilometers and rounded to the nearest whole number?

1 thought on “charlyn walks completely around the boundary of a square whose sides are each 55 km long. from any point on her path she can see e”

  1. The area of the region consisting of all the points Charlyn can see during her walk is equal to, A = 4840 km.
    Charlyn is walking around the boundary of square A, which is 55 km long, and she has a horizontal vision of 11 km.
    So as she walks around the square of 55 km, let there be another square B which lies outside square A, which is created due to her 11 km field of vision.
    length of sides of square B = 55+(2×11) which is equal to 77 km.
    And as she walks around the square of 55 km, let there be yet another square C which lies inside square A, which is created due to her 11 km field of vision.
    length of sides of square C = 55-(2×11) which is equal to 33 km.
    The area that Charlyn can see throughout her walk is equal to,
    A = Area of square B – Area of square C.
    The area of square B = Side² = 77² = 5929.
    The area of square C = Side² = 33² = 1089.
    A = 5929 – 1089.
    A = 4840 km.
    Learn more about areas at
    #SPJ4

    Reply

Leave a Comment