You are looking down on a single coil in a constant magnetic field B = 1.2 T which points directly into of the screen. The dimensions of the

Question

You are looking down on a single coil in a constant magnetic field B = 1.2 T which points directly into of the screen. The dimensions of the coil go from a = 8 cm and b = 17 cm, to a* = 16 cm and b* = 22 cm in t = 0.04 seconds. If the coil has resistance that remains constant at 1.2 ohms. What would be the magnitude of the induced current in amperes?

Doris · Answer

Answer:   The  current is I  =  0.5425   A   Explanation:   From the question we are told that       The  magnetic field is  B  =  1.2   T       The first length is  a =  8   cm  =  0.08   m       The  second length is  a^*  = 16   cm  =  0.16   m       The first width is  b  =  17   cm  =  0.17   m        The second  width is  b^*  =  22   cm  =  0.22   m       The time interval  is  dt =  0.04   s        The resistance is  R =  1.2    Omega  Generally the first area is         A =  a * b   =>    A =  0.08 *  0.17  =>     A =  0.0136     m^2  The second area is           A^*  =  a^*  * b^*  =>   A^*  =  0.16 * 0.22  =>     A^*  =  0.0352   m^2    Generally the induced emf is mathematically represented as            epsilon  = -   frac{ B  * [A^*  -  A]}{dt}  This negative show that it is moving in the opposite direction of the motion producing it   =>   | epsilon | =   frac{ 1.2 * [ 0.0352-0.0135]}{0.04}  =>    | epsilon |  =  0.651   V  The induced current is         I  =   frac{| epsilon|}{R}  =>   I  =   frac{ 0.651}{1.2}  =>   I  =  0.5425   A

Leave a Comment Cancel reply

In a half hour, 1 inch of snow fell in Massachusetts. If the snow continues at this rate, how many inches of snow would fall in 1 hour?

A researcher would like to estimate p, the proportion of U.S. adults who support recognizing civil unions between gay or lesbian couples.