write the equation of the line for the following table of values.

x. -3 -5 -7 -9 -11

y. -16 -26 -36 -46 -56

Plz helppp 35 points:)

write the equation of the line for the following table of values.

x. -3 -5 -7 -9 -11

y. -16 -26 -36 -46 -56

Plz helppp 35 points:)

Answer:We conclude that the equation of the line is:

Step-by-step explanation:The slope-intercept form of the line equation

[tex]y = mx+b[/tex]

where

Given the data table

x -3 -5 -7 -9 -11

y -16 -26 -36 -46 -56

From the table taking two points

Determining the slope between (-3, -16) and (-5, -26)

[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(-3,\:-16\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-26\right)[/tex]

[tex]m=\frac{-26-\left(-16\right)}{-5-\left(-3\right)}[/tex]

[tex]m=5[/tex]

Thus, the slope of the line is: m = 5

substituting m = 5 and (-3, -16) in the slope-intercept form of the line equation to determine the y-intercept b

[tex]y = mx+b[/tex]

-16 = 5(-3) + b

-16 = -15 + b

b = -16+15

b = 1

Thus, the y-intercept b = 1

now substituting m = 5 and b = 1 in the slope-intercept form of the line equation

[tex]y = mx+b[/tex]

[tex]y = 5x + 1[/tex]

Therefore, we conclude that the equation of the line is: