Write an equation in slope-intercept form (y=mx+b) for the line that has a slope of 12 and passes through the point (3, 20).
Answer:y=12x-16Step-by-step explanation:You want to find the equation for a line that passes through the point (3,20) and has a slope of 12.First of all, remember what the equation of a line is:y = mx+bWhere:m is the slope, andb is the y-interceptTo start, you know what m is; it’s just the slope, which you said was 12. So you can right away fill in the equation for a line somewhat to read:y=12x+b.Now, what about b, the y-intercept?To find b, think about what your (x,y) point means:(3,20). When x of the line is 3, y of the line must be 20.Because you said the line passes through this point, right?Now, look at our line’s equation so far: . b is what we want, the 12 is already set and x and y are just two “free variables” sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (3,20).So, why not plug in for x the number 3 and for y the number 20? This will allow us to solve for b for the particular line that passes through the point you gave!.(3,20). y=mx+b or 20=12 × 3+b, or solving for b: b=20-(12)(3). b=-16.The equation of the line that passes through the point (3,20) with a slope of 12isy=12x-16