Write an equation in slope-intercept form (y=mx+b) for the line that has a slope of 12 and passes through the point (3, 20).


  1. Answer:
    Step-by-step explanation:
    You want to find the equation for a line that passes through the point (3,20) and has a slope of 12.
    First of all, remember what the equation of a line is:

    y = mx+b
    m is the slope, and
    b is the y-intercept
    To start, you know what m is; it’s just the slope, which you said was 12. So you can right away fill in the equation for a line somewhat to read:
    Now, what about b, the y-intercept?

    To find b, think about what your (x,y) point means:
    (3,20). When x of the line is 3, y of the line must be 20.
    Because you said the line passes through this point, right?
    Now, look at our line’s equation so far: . b is what we want, the 12 is already set and x and y are just two “free variables” sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (3,20).

    So, why not plug in for x the number 3 and for y the number 20? This will allow us to solve for b for the particular line that passes through the point you gave!.

    (3,20). y=mx+b or 20=12 × 3+b, or solving for b: b=20-(12)(3). b=-16.
    The equation of the line that passes through the point (3,20) with a slope of 12



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