Answers

1. Answer:

   y=12x-16

   Step-by-step explanation:

   You want to find the equation for a line that passes through the point (3,20) and has a slope of 12.
   

   First of all, remember what the equation of a line is:
   

   
   

   y = mx+b
   

   Where:
   

   m is the slope, and
   

   b is the y-intercept
   

   To start, you know what m is; it’s just the slope, which you said was 12. So you can right away fill in the equation for a line somewhat to read:
   

   y=12x+b.
   

   Now, what about b, the y-intercept?
   

   
   

   To find b, think about what your (x,y) point means:
   

   (3,20). When x of the line is 3, y of the line must be 20.
   

   Because you said the line passes through this point, right?
   

   Now, look at our line’s equation so far: . b is what we want, the 12 is already set and x and y are just two “free variables” sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (3,20).
   

   
   

   So, why not plug in for x the number 3 and for y the number 20? This will allow us to solve for b for the particular line that passes through the point you gave!.
   

   
   

   (3,20). y=mx+b or 20=12 × 3+b, or solving for b: b=20-(12)(3). b=-16.
   

   The equation of the line that passes through the point (3,20) with a slope of 12
   

   is
   

   
   

   y=12x-16

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