Write a slope-intercept equation for a line passing through the point (5,−4) that is parallel to the line 5x+6y=7. Then write a second equation for a line passing through the point (5,−4) that is perpendicular to the line 5x+6y=7. (The equation of the parallel line is y=-5/6x+1/6)

The equation of the perpendicular line is __

Answer: Therefore, the equation of the line that is perpendicular to the given line and passes through the point (5, -4) is y = (6/5)x – 10.Step-by-step explanation: