The quadratic function in standard form whose graph passes through the given points (10,0), (1,0), and (4,3) is; y = 0.2x² – 2.2x + 2

The standard form of a quadratic equation is;

y = ax² + bx + c

where a, b and c are constants

Thus, for the coordinate (10,0), we have;

0 = a(10)² + b(10) + c

100a + 10b + c = 0  —–(1)

For the coordinate (1,0), we have;

0 = a(1)² + b(1) + c

a + b + c = 0   —–(2)

For the coordinate (4,3), we have;

3 = a(4)² + b(1) + c

16a + b + c = 3  ——(3)

Using online simultaneous equation, we have;

a = 0.2 and b = -2.2 and c = 2

The quadratic function is;

y = 0.2x² – 2.2x + 2

Read more about Quadratic Equations at; https://brainly.com/question/25841119

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