Question write a quadratic function in standard form whose graph passes through the given points (10,0), (1,0), and (4,3).

The quadratic function in standard form whose graph passes through the given points (10,0), (1,0), and (4,3) is; y = 0.2x² – 2.2x + 2 How to write the standard form of the quadratic equation? The standard form of a quadratic equation is; y = ax² + bx + c where a, b and c are constants Thus, for the coordinate (10,0), we have; 0 = a(10)² + b(10) + c 100a + 10b + c = 0 —–(1) For the coordinate (1,0), we have; 0 = a(1)² + b(1) + c a + b + c = 0 —–(2) For the coordinate (4,3), we have; 3 = a(4)² + b(1) + c 16a + b + c = 3 ——(3) Using online simultaneous equation, we have; a = 0.2 and b = -2.2 and c = 2 The quadratic function is; y = 0.2x² – 2.2x + 2 Read more about Quadratic Equations at; https://brainly.com/question/25841119 #SPJ1 Log in to Reply

quadratic functionin standard form whose graph passes through the given points (10,0), (1,0), and (4,3) is; y = 0.2x² – 2.2x + 2## How to write the standard form of the quadratic equation?

quadratic equationis;constantscoordinate(10,0), we have;coordinate(1,0), we have;coordinate(4,3), we have;simultaneous equation,we have;Quadratic Equationsat; https://brainly.com/question/25841119