Which is the general form of the equation of the circle shown? x2 y2 4x – 2y – 4 = 0 x2 y2 4x – 2y 2 = 0 x2 y² – 4x 2y – 4 = 0 x2 y² – 4x 2y 2 = 0

Which is the general form of the equation of the circle shown? x2 y2 4x – 2y – 4 = 0 x2 y2 4x – 2y 2 = 0 x2 y² – 4x 2y – 4 = 0 x2 y² – 4x 2y 2 = 0

general equationthat represents thecircleis x² + y² + 8x – 18y + 72 = 0## How to determine the circle equation?

centerof thecircleis given as:diameteris given as:radius (r)circle equationis then calculated using:general equationthat represents thecircleis x² + y² + 8x – 18y + 72 = 0circle equationsat: