Which is the general form of the equation of the circle shown? x2 y2 4x – 2y – 4 = 0 x2 y2 4x – 2y 2 = 0 x2 y² – 4x 2y – 4 = 0 x2

Which is the general form of the equation of the circle shown? x2 y2 4x – 2y – 4 = 0 x2 y2 4x – 2y 2 = 0 x2 y² – 4x 2y – 4 = 0 x2 y² – 4x 2y 2 = 0

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  1. The general equation that represents the circle is x² + y² + 8x – 18y + 72 = 0

    How to determine the circle equation?

    The center of the circle is given as:
    Center, (a,b) = (-4,9)
    The diameter is given as:
    d = 10
    Calculate the radius (r)
    r = 10/2 = 5
    The circle equation is then calculated using:
    (x – a)² + (y – b)² = r²
    So, we have:
    (x + 4)² + (y – 9)² = 5²
    Expand
    x² + 8x + 16 + y² – 18y + 81 = 25
    Collect like terms
    x² + y² + 8x – 18y + 16 + 81 – 25 = 0
    Evaluate
    x² + y² + 8x – 18y + 72 = 0
    Hence, the general equation that represents the circle is x² + y² + 8x – 18y + 72 = 0
    Read more about circle equations at:

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