Which function has a vertex at the origin?
f(x) = (x + 4)²2
f(x) = x(x-4)
f(x) = (x-4)(x + 4)
f(x) = -x²

Question

Which function has a vertex at the origin?  f(x) = (x + 4)²2  f(x) = x(x-4)  f(x) = (x-4)(x + 4)  f(x) = -x²

yenoanh · Answer

Answer:   f(x) = -x²   Step-by-step explanation:   Writing f(x) = -x² in vertex form gives f(x)=-(x-0)^2+0 which shows that the vertex (h,k) is at (0,0)  The other equations written in vertex form do not have (h,k) = (0,0)

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