Question

What percentage of the original activity in the sample remains after 17.5 days? half life calculation

Answers

  1. The percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.

    What is half life?

    Half-life is the time required for a quantity to reduce to half of its initial value.
    The original activity in the sample that remains after 17.5 days is calculated from half life equation as shown below;
    N(t) = No(¹/₂)^t/h
    where;
    • N(t) is the mass of the substance remaining
    • No is the initial mass of the substance
    • t is time elapsed = 17.5 days
    • h is the half life of the substance
    percentage of the original activity in the sample remains after 17.5 days;
    = N(t) / No x 100%
    Thus, the percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.
    Learn more about half life here: https://brainly.com/question/2320811
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