Question What percentage of the original activity in the sample remains after 17.5 days? half life calculation

The percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%. What is half life? Half-life is the time required for a quantity to reduce to half of its initial value. The original activity in the sample that remains after 17.5 days is calculated from half life equation as shown below; N(t) = No(¹/₂)^t/h where; N(t) is the mass of the substance remaining No is the initial mass of the substance t is time elapsed = 17.5 days h is the half life of the substance percentage of the original activity in the sample remains after 17.5 days; = N(t) / No x 100% Thus, the percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%. Learn more about half life here: https://brainly.com/question/2320811 #SPJ4 Reply

percentageof theoriginal activityin the sample remains after 17.5 days is obtained as N(t) / No x 100%.What is half life?Half-lifeis the time required for a quantity to reduce to half of its initial value.original activityin the sample that remains after 17.5 days is calculated from half life equation as shown below;percentageof the original activity in the sample remains after 17.5 days;percentageof theoriginal activityin the sample remains after 17.5 days is obtained as N(t) / No x 100%.half lifehere: https://brainly.com/question/2320811