What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s July 12, 2021 by Latifah What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s
Answer: [tex]K=0.023J[/tex] Explanation: From the question we are told that: Mass [tex]m=0.15[/tex] Velocity [tex]v=0.5m/s[/tex] Angular Velocity [tex]\omega=8.4rad/s[/tex] Generally the equation for Kinetic Energy is mathematically given by [tex]K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)[/tex] [tex]K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))[/tex] [tex]K=0.023J[/tex] Reply
Answer:
[tex]K=0.023J[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=0.15[/tex]
Velocity [tex]v=0.5m/s[/tex]
Angular Velocity [tex]\omega=8.4rad/s[/tex]
Generally the equation for Kinetic Energy is mathematically given by
[tex]K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)[/tex]
[tex]K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))[/tex]
[tex]K=0.023J[/tex]