What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s

What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s

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  1. Answer:

    [tex]K=0.023J[/tex]

    Explanation:

    From the question we are told that:

    Mass [tex]m=0.15[/tex]

    Velocity [tex]v=0.5m/s[/tex]

    Angular Velocity [tex]\omega=8.4rad/s[/tex]

    Generally the equation for Kinetic Energy is mathematically given by

    [tex]K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)[/tex]

    [tex]K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))[/tex]

    [tex]K=0.023J[/tex]

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