Question What is the solution to 3/2b + 5 < 17? Explain How. (1) b < 8 (2) b > 8 (3) b < 18 (3) b > 18
3/2b + 5 < 17 We subtract 5 from both sides of the inequality. 3/2b + 5 – 5 < 17 – 5 3/2 b < 12 Multiply both sides by 2/3. ( 2/3) * (3/2b) < (2/3) * 12 b < 8 Therefore, the correct option is alternative “A”. We would think that it is option B, but the only difference is that it changes the direction of the sign. Reply
Answer: [A]: ” b < 8 ” ._____ Step-by-step explanation: Given: Find the solution to: ” 3/2b + 5 < 17 ” ; and choose from the answer choices. So; we have: (3/2)b + 5 < 17 ; Now, subtract “5” from each side of this inequality: (3/2)b + 5 − 5 < 17 − 5 ; To get: (3/2)b < 12 ; Now, let’s multiply Each Side of this inequality by “2” ; to get rid of the fraction: ” 2*(3/2)b < 12*2 ” ; {Note: ” ” } ; Note: To simplify: ” ” ; Note the “2” in the denominator in the “first term” ; And: The “2” in the denominator in the “second term” ; Both “cancel out” to “1” ; since: “[ 2 / 2 = 2÷2 = 1 ]” ; And: we have: ” ” }; _____ and rewrite: ” 3b < 24 ” ; Now, divide Each side of the inequality by “3” ; to isolate “b” on one side of the inequality; and to solve for “x” ; _____ ” 3b/3 < 24/3 ” ; to get: _____ “ b < 8 ” ; which corresponds to the correct answer: Answer choice: [A]: ” b < 8 ” ._____ Hope this is helpful to you! Best wishes!_____ Reply
3/2b + 5 < 17
3/2b + 5 – 5 < 17 – 5
3/2 b < 12
( 2/3) * (3/2b) < (2/3) * 12
b < 8
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Find the solution to: ” 3/2b + 5 < 17 ” ; and choose from the answer choices.
(3/2)b + 5 − 5 < 17 − 5 ;
(3/2)b < 12 ;
Note the “2” in the denominator in the “first term” ;
and rewrite:
” 3b < 24 ” ;
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” 3b/3 < 24/3 ” ;
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