Question What is the probability that a randomly selected day from 2013 will have a group trades total within 85,000 of the mean?

the probability that a randomly selected day from 2013 will have a group trades total within 85,000 of the mean is 0.1328 How to solve for the probability Mean (u) = 3421439 How to solve for the probability Standard deviation = 508638.08 We know that: z = x-u/sd Now, P(u – 85000 <= x <= u + 85000) u = 3421439 We have to put thus in the formula above = P(3421439 – 85000 and 3421439 + 85000) = P(3336439, 3506439) = (3336439 – 3421439) / 508638.08 ,3506439-3421439) / 508638.08) = prob(-0.1671 and 0.1671 under the z table this is = 0.5664 – 0.4336 = 0.1328 Read more on probability here: https://brainly.com/question/24756209 #SPJ4 Log in to Reply

probabilitythat arandomlyselected day from 2013 will have a group trades total within 85,000 of themeanis0.1328## How to solve for the probability

Mean(u) = 3421439## How to solve for the probability

Standard deviation= 508638.08probabilityhere: https://brainly.com/question/24756209