Question

What is the probability that a randomly selected day from 2013 will have a group trades total within 85,000 of the mean?

Answers

  1. the probability that a randomly selected day from 2013 will have a group trades total within 85,000 of the mean is  0.1328

    How to solve for the probability

    Mean (u) = 3421439

    How to solve for the probability

    Standard deviation = 508638.08
    We know that:
    z = x-u/sd
    Now,
    P(u – 85000 <= x <= u + 85000)
    u = 3421439
    We have to put thus in the formula above
    = P(3421439 – 85000 and
    3421439 + 85000)
    = P(3336439,  3506439)
    = (3336439 – 3421439) / 508638.08
    ,3506439-3421439) / 508638.08)
    = prob(-0.1671 and 0.1671
    under the z table this is
    = 0.5664 – 0.4336
    = 0.1328
    Read more on probability here: https://brainly.com/question/24756209
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