What is the gravitational force between the Earth

(mEarth = 5.98 x 1024 kg, rEarth = 6.378 x 106 m)

and a 15,000 kg satellite in Earth’s orbit 575-km above Earth’s surface?

Answer:

____________ Newtons

I really need help on this! Can someone please help? Thank you!

Answer:

17.7MN

Explanation:

Given Data

m1 = 5.98 x 10^24 kg

m2= 15,000 kg

R= 6.378 x 10^6 m+575-km

R= 6.378 x 10^3+575*10^3-km

R= 581378m

G = 6.673 x 10-11 N m^2/kg2

This net centripetal force is the result of the gravitational force that attracts the satellite towards the central body and can be represented as

F =GM1M2 / R^2

F =6.673 x 10-11* 5.98 x 10^24*15,000 / 581378^2

F =6.673 x 10^-11* 5.98 x 10^24*15,000 / 581378^2

F= 39.90454*10^13*15,000/ 581378^2

F= 598.5681*10^16/338000378884

F= 17709095.5335N

F= 17.7MN