What is the gravitational force between the Earth
(mEarth = 5.98 x 1024 kg, rEarth = 6.378 x 106 m)
and a 15,000 kg satellite in Earth’s orbit 575-km above Earth’s surface?
Answer:
____________ Newtons
I really need help on this! Can someone please help? Thank you!
Answer:
17.7MN
Explanation:
Given Data
m1 = 5.98 x 10^24 kg
m2= 15,000 kg
R= 6.378 x 10^6 m+575-km
R= 6.378 x 10^3+575*10^3-km
R= 581378m
G = 6.673 x 10-11 N m^2/kg2
This net centripetal force is the result of the gravitational force that attracts the satellite towards the central body and can be represented as
F =GM1M2 / R^2
F =6.673 x 10-11* 5.98 x 10^24*15,000 / 581378^2
F =6.673 x 10^-11* 5.98 x 10^24*15,000 / 581378^2
F= 39.90454*10^13*15,000/ 581378^2
F= 598.5681*10^16/338000378884
F= 17709095.5335N
F= 17.7MN