What is the general form of the equation for the given circle centered at o(0, 0)? a. x2 y2 41 = 0 b. x2 y2 − 41 = 0 c. x2 y2 x y − 41 = 0 d. x2 y2 x − y − 41 = 0

Answers

The general form of the equation for the given circle centered at o(0, 0)is x² + y² – 41 = 0.

According to the question,

The general form of the equation for the given circle centered at o(0, 0)is (x-h)² + (y-k)² = r².

The given equation is x² + y² – 41 = 0 which is also represented by

(x-0)² + (y-0)² = -(√41)². This is not possible.

The given equation is x² + y² – 41 = 0 which is also represented by (x-0)² + (y-0)² = (√41)²This means that the circle is centered at (0,0). Thus, the equation is correct

The given equation is x² + y² +x+ y- 41 = 0 which is also represented by (x+1/2)² + (y+1/2)² = (√(83/2))²This means that the circle is centered at (-1/2,-1/2). Thus, this equation is incorrect.

The given equation is x² + y² +x- y- 41 = 0 which is also represented by (x+1/2)² + (y-1/2)² = (√(83/2))²This means that the circle is centered at (1/2,-1/2). Thus, this equation is incorrect.

Hence, the general form of the equation for the given circle centered at o(0, 0)is x² + y² – 41 = 0.

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