Question What is the equation of the line in point-slope form? y 4 = (x 4) y – 4 = (x 4) y – 0 = 2(x – 4) y – 4 = 2(x – 0)

The equation of line is y+4 = 1/2*(x+4). What is point- slope form? The point–slope form of a line with slope ‘m’ and passing through a point (a, b) is given by (y-b)= m(x-a) Given: As, the points (4, 0) and (-4, -4) are two points on the straight line. slope of line= -4-0/ -4-4 m= 1/2 Now, line passes through the point (-4, -4), equation of the line is y-(-4) = m(x-(-4)) y+4 = 1/2*(x+4) Hence, required point–slope form of the graphed line is y+4 = 1/2*(x+4) Learn more about this concept here: https://brainly.com/question/2616640 #SPJ1 Log in to Reply

equationof line isy+4 = 1/2*(x+4).## What is point- slope form?

point–slopeform of alinewithslope ‘m’andpassingthrough a point(a, b)is given by(y-b)= m(x-a)Given:(4, 0)and(-4, -4)aretwo pointson thestraightline.m= 1/2linepassesthrough the point(-4, -4),equationof thelineisy+4 = 1/2*(x+4)requiredpoint–slope formof the graphed line isy+4 = 1/2*(x+4)concepthere:#SPJ1