What is the equation in standard form of the line that passes through the point (6,-1) and is parallel to the line represented by.
Answer:Step-by-step explanation:y = mx + bIn this equation, m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).To find the equation of a line that passes through a given point (x1, y1) and is parallel to another line with slope m, you can use the point-slope formula:y – y1 = m(x – x1)In this case, the line passes through the point (6, -1) and is parallel to the line represented by y = mx + b. Substituting these values into the point-slope formula, we get:y – (-1) = m(x – 6)This is the equation of the line in point-slope form. To put the equation in standard form, we can rearrange the terms to get:y = mx – 6m + 1This is the equation of the line in standard form.I hope this helps! Let me know if you have any further questions.