Question

What is the equation in standard form of the line that passes through the point (6,-1) and is parallel to the line represented by.

Answers

  1. Answer:
    Step-by-step explanation:
    y = mx + b
    In this equation, m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).
    To find the equation of a line that passes through a given point (x1, y1) and is parallel to another line with slope m, you can use the point-slope formula:
    y – y1 = m(x – x1)
    In this case, the line passes through the point (6, -1) and is parallel to the line represented by y = mx + b. Substituting these values into the point-slope formula, we get:
    y – (-1) = m(x – 6)
    This is the equation of the line in point-slope form. To put the equation in standard form, we can rearrange the terms to get:
    y = mx – 6m + 1
    This is the equation of the line in standard form.
    I hope this helps! Let me know if you have any further questions.

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