Answer: The answer is 2.44 units Step-by-step explanation: The distance between two points can be found by using the formula [tex]d = \sqrt{ ({x1 – x2})^{2} + ({y1 – y2})^{2} } \\ [/tex] where (x1 , y1) and (x2 , y2) are the points From the question the points are J(5.4,-3.2) and K(4,-1.2) The distance between them is [tex] |JK| = \sqrt{ ({5.4 – 4})^{2} + ({ – 3.2 + 1.2})^{2} } \\ = \sqrt{( {1.4})^{2} + ({ – 2})^{2} } \\ = \sqrt{1.96 + 4} \\ = \sqrt{5.96} \: \: \: \: \: \: \: \: \\ = 2.44131112[/tex] We have the final answer as 2.44 units Hope this helps you Log in to Reply

Answer:The answer is

## 2.44 units

Step-by-step explanation:The distance between two points can be found by using the formula

[tex]d = \sqrt{ ({x1 – x2})^{2} + ({y1 – y2})^{2} } \\ [/tex]

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

J(5.4,-3.2) and K(4,-1.2)

The distance between them is

[tex] |JK| = \sqrt{ ({5.4 – 4})^{2} + ({ – 3.2 + 1.2})^{2} } \\ = \sqrt{( {1.4})^{2} + ({ – 2})^{2} } \\ = \sqrt{1.96 + 4} \\ = \sqrt{5.96} \: \: \: \: \: \: \: \: \\ = 2.44131112[/tex]

We have the final answer as

## 2.44 units

Hope this helps you