Answer: The answer is 2.44 units Step-by-step explanation: The distance between two points can be found by using the formula [tex]d = \sqrt{ ({x1 – x2})^{2} + ({y1 – y2})^{2} } \\ [/tex] where (x1 , y1) and (x2 , y2) are the points From the question the points are J(5.4,-3.2) and K(4,-1.2) The distance between them is [tex] |JK| = \sqrt{ ({5.4 – 4})^{2} + ({ – 3.2 + 1.2})^{2} } \\ = \sqrt{( {1.4})^{2} + ({ – 2})^{2} } \\ = \sqrt{1.96 + 4} \\ = \sqrt{5.96} \: \: \: \: \: \: \: \: \\ = 2.44131112[/tex] We have the final answer as 2.44 units Hope this helps you Log in to Reply
Answer:
The answer is
2.44 units
Step-by-step explanation:
The distance between two points can be found by using the formula
[tex]d = \sqrt{ ({x1 – x2})^{2} + ({y1 – y2})^{2} } \\ [/tex]
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
J(5.4,-3.2) and K(4,-1.2)
The distance between them is
[tex] |JK| = \sqrt{ ({5.4 – 4})^{2} + ({ – 3.2 + 1.2})^{2} } \\ = \sqrt{( {1.4})^{2} + ({ – 2})^{2} } \\ = \sqrt{1.96 + 4} \\ = \sqrt{5.96} \: \: \: \: \: \: \: \: \\ = 2.44131112[/tex]
We have the final answer as
2.44 units
Hope this helps you