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1. The conditional probability that, when flipping a non-biased coin four times, there are at least two heads, given that the first flip is a head, is 3/4.

   Calculating the Conditional Probability:

   Let us assume that getting a head in the first flip of coin is event B

   Also, let us assume that getting a head in on of the remaining three flips is A

   Then we have to find the probability of A given B, that is, P(A|B).

   The formula for conditional probability is given as follows,

   P(A|B) = P (A∩B) / P(B)

   The probability of getting two heads, P(A∩B) = 3/8

   The probability of getting head in the first flip, P(B) = 1/2

   ∴ P(A|B) = (3/8) / (1/2)

   P(A|B) = 3/4

   Thus,  the conditional probability of getting at least two heads, given that the first flip is a head is 3/4.

   Learn more about probability here:

   https://brainly.com/question/11234923

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