Question

What is the change in internal energy if 60 J of heat are released from a
system and 20 J of work is done on the system? Use AU = Q-W.

Answers

  1. Answer:

    60 J of heat are released from the system: Q=-60 J

    20 J of work is done on the system: W=-20 J

    ∆U=Q-W

    ∆U=-60-(-20)

    ∆U=-40 J

    Explanation:

    If the heat is released from the system, Q should be negative.

    If the heat is gained by the system, Q should be positive.

    If the work is done on the system, W should be negative.

    If the work is done by the system, W should be positive.

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