What is an equation of the line that passes through the point (8,-4)(8,−4) and is parallel to the line x-4y=12x−4y=12?

Answers

the equation of the line that is parallel to the line and goes through the place where it intersects it at (8, -4) is mathematically given as

x – 4y = 12 is x – 4y = – 8.

What is an equation of the line that passes through the point (8,-4)(8,−4) and is parallel to the line x-4y=12x−4y=12?

If the slopes of two lines, m1 and m2, are equal, then the lines are parallel; if the slopes are not equal, then the lines are perpendicular.

In the question, we are asked for the equation of the line that is parallel to the line x – 4y = 12 and goes through the place where it is represented by the coordinates (8, -4).

The given line can be shown as:

x – 4y = 12,

We may determine the slope of the line by comparing it to its slope-intercept form, which is written as y = mx + b. The slope of the line is 1/4.

The slope, m = 1/4, will also be present on the line that is parallel to this one. The necessary line goes through the location in question (8, -4).

Considering the one-point formula, (y – y₁) = m(x – x₁), we can write the required equation as:

y – (-4) = (1/4)(x – 8),

Therefore

x – 4y = – 8.

In conclusion, the equation of the line that is parallel to the line and goes through the place where it intersects it at (8, -4) x – 4y = 12 is x – 4y = – 8.

parallelto the line and goes through the place where itintersectsit at (8, -4) is mathematically given as## What is an equation of the line that passes through the point (8,-4)(8,−4) and is parallel to the line x-4y=12x−4y=12?

slopesof two lines, m1 and m2, areequal, then the lines are parallel; if the slopes are not equal, then the lines areperpendicular.equationof the line that is parallel to the line x – 4y = 12 and goes through the place where it is represented by the coordinates (8, -4).slope,m = 1/4, will also be present on the line that isparallelto this one. The necessary line goes through thelocationin question (8, -4).one-point formula, (y – y₁) = m(x – x₁), we can write the requiredequationas:parallel linesat