Question What are the y-intercept and the asymptote of g(x) = 3x – 5? (0, –5); y = 3 (0, –2); y = 5 (0, –4); y = –5 (0, 5); y = –3

The y-intercept of the equation g(x) = 3^x – 5 is (0, -4) and the asymptote of the equation g(x) = 3^x – 5 is y = -5 How to determine the y-intercept? The equation of the function g(x) is given as: g(x) = 3^x – 5 The y-intercept is a point on the graph where the value of x is 0 This is represented by x= 0 or (0, y) This means that we substitute 0 for x in the above equation So, we have: g(0) = 3^0 – 5 Evaluate the exponent 3^0 g(0) = 1 – 5 Evaluate the difference of 1 and 5 g(0) = -4 Rewrite this point as (0, -4) This means that the y-intercept of the equation g(x) = 3^x – 5 is (0, -4) How to determine the asymptote? The equation of the function g(x) is given as: g(x) = 3^x – 5 The asymptote is a point on the graph where that is parallel to the graph In the above equation, we have: g(x) = 3^x – 5 Express the radical as 0 y = 0 – 5 Evaluate the difference of 0 and 5 y = -5 This means that the asymptote of the equation g(x) = 3^x – 5 is y = -5 Read more about asymptote at: https://brainly.com/question/1851758 #SPJ1 Reply

y-interceptof theequationg(x) = 3^x – 5 is (0, -4) and theasymptoteof theequationg(x) = 3^x – 5 is y = -5## How to determine the y-intercept?

equationof thefunctiong(x) is given as:y-interceptis a point on thegraphwhere the value of x is 0equationy-interceptof theequationg(x) = 3^x – 5 is (0, -4)## How to determine the asymptote?

equationof thefunctiong(x) is given as:asymptoteis a point on thegraphwhere that is parallel to the graphasymptoteof theequationg(x) = 3^x – 5 is y = -5asymptoteat: