We write the integers from 1 to 150 inclusive. What is the total number of digits that must be written?
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Answer:342Step-by-step explanation:First, there are 9 one-digit numbers, so 9×1=9. Next, there are 90 two-digit numbers, so 90×2=180. There are 51 numbers between 100-150, so 51×3=153. Now, we do 9+180+153=342 digits.
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Answer:Step-by-step explanation:SolutionBreak the numbers down by the number of digits in that sequence.Number of digits 1 to 9 = 9Number of digits from 10 to 99There are 90 numbers between 10 and 99Each has 2 digitsThe total number of digits is 180Number of digits from 100 to 150There are 51 numbers between 100 and 150Each has 3 digitsThe total number of digits = 3*51 153 AddTotal number of digits = 342Answer: 342