Use the following situation to answer the questions that follow: A ball is thrown up in the air, and it’s height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32t + 6.

Describe in detail (using formulas and/or specific steps needed) TWO ways to find the maximum height reached by the ball.

Answer:1) find the verted of the parabols

[-b/2a, f(-b/2a)]

-32/-32 = 1 …. -16+32+6 = 22

2) take the derivative and set = to 0

-32t+32 = 0

t = 1 …..height = 22

Step-by-step explanation: