Question Use an addition or subtraction formula to simplify the equation. sin(3Î¸) cos(Î¸) â cos(3Î¸) sin(Î¸) = 0. Find all solutions in the interval [0, 2].

The solutions in the interval [0, 2] is the θ=0,π/2,π,π3/2. According to the statement we have to find that the all solutions of the given statement in the interval [0, 2]. So, For this purpose, So According to the trigonometry now lets take the inverse sin of both sides to solve, sin^-1(sin(2θ))=sin^-1(0) 2θ=sin-1(0) So you can either plug that into a calculator or just remember (from the unit circle) that the sine is equal to zero at 0 AND at π 2θ=0,π But we’re not done because the sine is periodic which means there will be solutions every trip around the unit circle (2π) So 2θ=0+N^2π and π+N^2π where N=0,+/-1,+/-2,etc… But we’re looking for values of θ so we have to divide everything by 2 θ=0+Nπ and π/2+Nπ Now we just have to find the values of N that yield solutions on the interval [0,2π] N=0 gives 0 and π/2 N=1 gives π and π3/2 So the full solution set is θ=0,π/2,π,π3/2; So, The solutions in the interval [0, 2] is the θ=0,π/2,π,π3/2. Learn more about interval here https://brainly.com/question/1600302 #SPJ4 Reply

solutionsin the interval [0, 2] is the θ=0,π/2,π,π3/2.trigonometrysolutionsin the interval [0, 2] is the θ=0,π/2,π,π3/2.intervalhere