Two masses, each weighing 1.0 × 103 kilograms and moving with the same speed of 12.5 meters/second, are approaching each other. They have a head-on collision and bounce off away from each other. Assuming this is a perfectly elastic collision, what will be the approximate kinetic energy of the system after the collision?

A. 1.6 × 105 joules

B. 2.5 × 105 joules

C. 1.2 × 103 joules

D. 2.5 × 103 joules

Answer:A. 1.6 × 105 joules

Explanation:As per the question, the data given in the question is as follows

Number of masses = 2

Each weightage = [tex]1.0 \times 2.3[/tex]

Speed = 12.5 meters/ second

Based on the above information, the approximate kinetic energy after the collision is

A perfectly elastic collision is described as one where the collision does not cause any loss of kinetic energy.

So we sum the kinetic energy of each kind of system which is given below:

Kinetic energy is

[tex]= 0.5(1.0 \times 10^3) (12.5)^2 + 0.5 (1.0 \times 10^3) (12.5 )^2[/tex]

= 156250 J

[tex]= 1.6 \times 10^5 J[/tex]