Two friends are planning for a gathering. the food budget is modeled by one half times the absolute value of the quantity x minus 120 end quantity equals 10 comma where x is the amount spent on food. what are the least and greatest amounts that the two friends could spend on food? $50, $70 $100, $140 $110, $130 $115, $125
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The least amount is $100 and greatest amount is $140.For given question,We have been given the food budget is modeled by an equation,1/2 |x – 120| = 10where x is the amount spent on food.We need to find the least and greatest amounts that the two friends could spend on food.⇒ 1/2 |x – 120| = 10⇒ |x – 120| = 20We can observe that above equation contains absolute vale function.⇒ x – 120 = ±20⇒ x – 120 = -20 or x – 120 = 20⇒ x = 120 – 20 or x = 120 + 20⇒ x = 100 or x = 140Therefore, the least amount is $100 and greatest amount is $140.Learn more about the absolute value here:https://brainly.com/question/22716244#SPJ4