Two fair, $6$-sided dice are thrown. What is the probability that the product of the two numbers is a multiple of $5$
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10/36, or about 28%1 combinations that yields 2 = 1 and 12 combinations that yield 3 = 1 and 2, 2 and 13 combinations that yield 4 = 1 and 3, 2 and 2, 3 and 14 combinations that yield 5 = 1 and 4, 2 and 3, 3 and 2, 4 and 1So 10 total combinations could create 5 or less out of 36 total combinations.When you roll a pair of dice the are 36 equally likely outcomes. This can be found by taking the number of outcomes on a standard die, six, and raising it to the power of the number of times you are rolling the die, two. 6^2 = 36.The no of favorable outcomes are 10 of the situation given, so we got the desired result.Learn more about probability here https://brainly.com/question/24756209#SPJ4