Two components of a minicomputer have the following joint pdf for their useful lifetimes X and Y. (If an answer doesn’t exist enter DNE.) f(x, y) = xe−x(1 + y) x ≥ 0 and y ≥ 0 0 otherwise Determine E(XY).

The value of E(XY) is equivalent or equal to -1 according to the joint pdf having function f(x, y) = xe^−x(1 + y) x ≥ 0 and y ≥ 0 0.

Given that:

f(x,y) = xe^-x(1+y), where x ≥ 0 and y ≥ 0 0.

E(XY) = ∫∞ ∫∞ xy. xe^−x(1 + y) dx dy

0 0

E(XY) = ∫∞ ∫∞ x^2y . e^−x(1 + y) dx dy

0 0

E(XY) = ∫∞ x^2 . e^−x (∫∞ y e^-xy dy) dx

0 0

E(XY) = ∫∞ x^2 . e^−x (-1/x) dx

0

E(XY) = – ∫∞ x . e^−x dx

0

E(XY) = – 1

Two components of a minicomputer have the following joint pdf for their useful lifetimes X and Y are equal to i.e. E(XY) = -1.

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valueof E(XY) isequivalentor equal to -1 according to the joint pdf havingfunctionf(x, y) = xe^−x(1 + y) x ≥ 0 and y ≥ 0 0.componentsof aminicomputerhave the following joint pdf for their usefullifetimesX and Y are equal to i.e. E(XY) = -1.functionvisit: brainly.com/question/5975436