Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and then, without replacement, a face card? Express your answer as a fraction or a decimal number rounded to four decimal places
Question
Answer:
0.0181 probability of choosing a king and then, without replacement, a face card.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability of choosing a king:
There are four kings on a standard deck of 52 cards, so:
[tex]P(A) = \frac{4}{52} = \frac{1}{13}[/tex]
Probability of choosing a face card, considering the previous card was a king.
12 face cards out of 51. So
[tex]P(B|A) = \frac{12}{51}[/tex]
What is the probability of choosing a king and then, without replacement, a face card?
[tex]P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181[/tex]
0.0181 probability of choosing a king and then, without replacement, a face card.