Today, the population of Canyon Falls is 22{,}50022,50022, comma, 500 and the population of Swift Creek is 15{,}20015,20015, comma, 200. The population of Canyon Falls is decreasing at the rate of 740740740 people each year while the population of Swift Creek is increasing at the rate of 1{,}5001,5001, comma, 500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls
Answer:
10 years
Step-by-step explanation:
Given :
Population of Canyon falls = 22500
Rate of decrease = 740 per year
Population after x years :
f(x) = 22500 – 740x ; x = number of years
Population of Swift Creek = 15200
Rate of Increase = 1500 per year
Population after x years :
f(x) = 15200 + 1500x ; x = number of years
Number of years when, population of swift creek will be twice that of Canyon falls
15200 + 1500x = 2(22500 – 740x)
15200 + 1500x = 45000 – 1480x
15200 – 45000 = – 1480x – 1500x
-29800 = – 2980x
x = 29800 / 2980
x = 10
After 10 years