Question Three numbers have the sum of 112. The first number is twice the second and the third number us twice the first. What is the smallest of the 3 numbers?

Answer: x = 16 Step-by-step explanation: Let the second number be x. The first number = 2x The third number = 2×2x = 4x 2x + x + 4x = 112 7x = 112 x = 112/7 x = 16 Log in to Reply

Answer:x=16Step-by-step explanation:x.2x2×2x4x2x+x4x1127x112x112/7x16