Three lorries each making five trips per day transport 2500 crates from a factory to a distributor in two days .how many lorries each making 6 trips a day are needed to transport 10000 such crates in a day
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Step-by-step explanation:3×5×2 = 30 lorry trips to deliver 2,500 crates.3 lorries, 5 trips per day, 2 daysthat means that one lorry trip transports2,500 / 30 = 250/3 = 83.33333… crates = 83 1/3 crates.now we need x lorries each making 6 trips per day in 1 day (so, 6 trips, period) to transport 10,000 crates.that looks likex × 6 × 83.33333… = 10,000x × 6 × 83 1/3 = 10,000x × (6×83 + 6 × 1/3) = 10,000x × (498 + 2) = 10,000500x = 10,000x = 20so, we need 20 lorries each doing 6 trips in one day to transport 10,000 crates in one day.these are altogether 20×6 = 120 lorry trips.that is 4 times the number of the original scenario (30 trips).and logically, when doing 4 times the work, we achieve 4 times the result (10,000 crates instead of 2,500).