Question The volume of a cylinder having height one and half of the radius is 12,936 m3 what minimum square cm of paper is needed to cover the curved surface area of the cylinder? The answer should be 1848m2. please solve my question.

(Pi)r^2 *3r/2 =12936 (Pi)r^3 = 12936*2/3 =8624 r^3 = 864 /(Pi) =8624* 7/22 = 2744 r= (2744^(1/3) = 14; h=21 2(Pi)rh = 2*(22/7) *14*21=1848 Solution 1848cm^2 Reply

(Pi)r^2 *3r/2 =12936

(Pi)r^3 = 12936*2/3 =8624

r^3 = 864 /(Pi) =8624* 7/22 = 2744

r= (2744^(1/3) = 14; h=21

2(Pi)rh = 2*(22/7) *14*21=1848

Solution

1848cm^2